32^(3-2x)=64

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Solution for 32^(3-2x)=64 equation: 



32^(3-2x)=64

We move all terms to the left:

32^(3-2x)-(64)=0

We add all the numbers together, and all the variables

32^(-2x+3)-64=0

We move all terms containing x to the left, all other terms to the right

32^(-2x+3)=64

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